2g^2-5g-8=0

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Solution for 2g^2-5g-8=0 equation:



2g^2-5g-8=0
a = 2; b = -5; c = -8;
Δ = b2-4ac
Δ = -52-4·2·(-8)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{89}}{2*2}=\frac{5-\sqrt{89}}{4} $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{89}}{2*2}=\frac{5+\sqrt{89}}{4} $

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